Question 105220
I'm assuming you mean like this, 
{{{(2x-4)/4<=(1+x)/3}}}
Multiply both sides by 3*4 to get rid of denominators. 
{{{3*cross(4)*(2x-4)/cross(4)<=cross(3)*4*(1+x)/cross(3)}}}
{{{3(2x-4)<=4(1+x)}}}
{{{6x-12<=4+4x)}}}Distribute on both sides. 
{{{6x-4x-12<=4+4x-4x)}}}Additive inverse of 4x. 
{{{2x-12<=4}}}
{{{2x-12+12<=4+12}}}Additive inverse of (-12).
{{{2x<=16}}}
{{{2x/2<=16/2}}}Multiplicative inverse of 2. 
{{{x<=8}}}
Check your answer. 
Let x=0, since x<8 then the equation should be true. 
{{{(2x-4)/4<=(1+x)/3}}}
{{{(2(0)-4)/4<=(1+0)/3}}}
{{{-1<=1/3}}}
True statement, as you expected. 
Let x=9, since x>9, then the equation should not be true. 
{{{(2(9)-4)/4<=(1+9)/3}}}
{{{(18-4)/4<=10/3}}}
{{{3.5<=3.333}}}
False statement, as you expected. 
{{{x<=8}}} Final answer.