Question 1148560
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Presumably this problem is intended as an exercise in using algebra to solve problems.  However, note that a little logical reasoning can get to the answer much faster, and with much less effort.<br>
(1) Each of the fractions is close to 1/2; so the sum of the three numbers is about 2*32=64.  So the three numbers are in the low 20s.<br>
(2) 3/5 of the first number is a whole number, so the first number must be a multiple of 5.  And since it is even, it must be a multiple of 10.<br>
(3) A number in the low 20s that is a multiple of 10 has to be 20.  So the three numbers are PROBABLY 20, 22, and 24.<br>
CHECK:
(3/5)*20 + (1/2)*22 + (3/8)*24 = 12+11+9 = 32<br>