Question 1148559
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FK = JH = 6, so the radius of the circle is OF+FK = OF+JH = 21.<br>
OC is also a radius of the circle, so OC = 21.<br>
Then triangle OFC is a right triangle and we know OF=15 and OC=21; the Pythagorean Theorem then tells us<br>
{{{FC = sqrt(21^2-15^2) = sqrt(441-225) = sqrt(216) = 6*sqrt(6)}}}<br>
Then the diagonals of the rhombus are 30 and 12*sqrt(6).<br>
The area of a rhombus is half the product of the diagonals:<br>
{{{A = (1/2)(30)(12*sqrt(6)) = 180*sqrt(6)}}}<br>