Question 1148548
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Added in 1990 and removed in 1997, the highest advertising sign in the world was a large letter I situated at the top of the 73-story 
First Interstate World Center building in Los Angeles. At a distance of 220 feet from a point <U>at the ground level</U> directly below the sign, 
the angle between the ground and the top of the sign was 77.79°. Approximate the height of the top of the sign.
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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Notice that I edited your post to make it more precise.

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;My editing is underlined.



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Let  y = the height of the top of the sign.


Then tan(77.79°) = {{{y/220}}},  which implies  y = 220*tan(77.79°) feet.


Use your calculator to get the value . . . 
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