Question 1148521
We are given that x=1672 and n=2388
ph=(x/n)=(1672/2388)=0.7
Significance level=1-confidence=1-0.95=0.05
Critical z-value=z(at alpha/2)=z(0.05/2)=z(at 0.025)=1.96(from z-table)
SE=Standard error of ph=SE={{{sqrt(ph*(1-ph)/n)}}}=0.009377
E=Critical z-value*SE=1.96*0.009377=0.01838
Margin of Error=E=0.01838