Question 105664
The sum of three consecutive integers is 33 more than the least of the integers.  Find the integers.
x=first integer
x+1=second integer
x+2= third integer
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x+x+1+x+2=x+2+33
3x+3=x+35
3x-x=35-3
2x=32
x=16
so the integers are;
16,17,18
:)