Question 1148359
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<pre>

If the area of the triangle is divided by these parallel segments in 6 equal parts,


then the ratio of areas of the largest triangle to the preceding triangle is  {{{6/5}}}.


If " k " is the similarity coefficient of the preceding triangle to the largest (original) triangle, then


    {{{k^2}}} = {{{5/6}}};


hence,  k = {{{sqrt(5/6)}}}.


It implies that the length of the segment under the question is  {{{sqrt(5/6)*32}}} cm.    <U>ANSWER</U>
</pre>

Solved.