Question 1148362
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With angle AOT 60 degrees and the radius OT=8, we can conclude that AO=16 and AT=8*sqrt(3).<br>
Then in right triangle XOT we have legs XT=8*sqrt(3)-m and OT=8, and hypotenuse XO=8+m.  So<br>
{{{8^2+(8*sqrt(3)-m)^2 = (8+m)^2}}}<br>
Solving that equation, the m^2 terms on the two sides cancel, leaving a linear equation in m, making it possible to find an exact value for m (in radical form).<br>