Question 1148311
Ray, Sam, & Tim had a total of $1017 at first.
r + s + t = 1017 
 Ray had the least amount of money. 
 The ratio of Sam to Tim's money is 4 to 3.
{{{s/t}}}= {{{4/3}}}
4t = 3s
t = {{{3/4}}}s
t = .75s
 After Ray and Sam each spent 1/3 of their money, the 3 boys had $798 left.
1017 - {{{1/3}}}(r+s) = 798
multiply by 3
3(1017) - (r+s) = 3(798)
3051 - r - s = 2394
-r - s = 2394 - 3051
-r - s = -657
multiply by -1
r + s = 657
r = (657-s)
:
In the first equation replace r with (657-s). Replace t with .75s
(657-s) + s + .75s = 1017
.75s = 1017 - 657
.75s = 360
s = 360/.75
s = $480 as Sam's amt
then
r = 657 - 480
r = $177 is how much did Ray had at first?