Question 105695
{{{3x^2+17x+45=12}}}
{{{3x^2+17x+45-12=12-12}}}
{{{3x^2+17x+33=0}}}
Use the quadratic formula,
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where a=3, b=17, c=33
 {{{x = (-17 +- sqrt( 17^2-4*3*33 ))/(2*3) }}}
 {{{x = (-17 +- sqrt( 289-396 ))/(6) }}} 
{{{x = (-17 +- sqrt( -107 ))/(6) }}}
{{{x = (-17 +- i(sqrt( 107 )))/(6) }}}