Question 1148202
.
<pre>

2000 = 1000*(1+0.07)^t   where " t " is the time, in years.


{{{2000/1000}}} = {{{1.07^t}}}


2 = {{{1.07^t}}}


Take the logarithm of both sides


log(2) = t*log(1.07)


t = {{{log((2))/log((1.07))}}} = 10.24 years.


<U>ANSWER</U>.  11 years is enough time.  10 years is not enough.
</pre>