Question 1148201
How do i make a quadratic equation from vertex point (4,-3) and point (6,-1)?
<pre>Vertex form of a quadratic: {{{matrix(1,3, y, "=", a(x - h)^2 + k)}}}
                          {{{matrix(1,3, - 1, "=", a(6 - 4)^2 + - 3)}}} ------- Substituting (4, - 3) for (h, k), and (6, - 1) for (x, y)
                          - 1 = 4a - 3
                          - 1 + 3 = 4a
                                2 = 4a
                               {{{matrix(1,7, 2/4, "=", "a,", or, 1/2, "=", a)}}}
{{{matrix(1,3, y, "=", a(x - h)^2 + k)}}}
{{{highlight_green(matrix(1,3, y, "=", (1/2)(x - 4)^2 - 3))}}} ----- Substituting {{{1/2}}} for a, and (4, - 3) for (h, k)
That's it!! Nothing complex or time-consuming, @ ALL!