Question 105780
Two obvious factors of 116 are 1 and 116
.
Next, notice that 116 is an even number, so it is divisible by 2. When you divide it by 2
the answer is 58. This means that 116 is also divisible by 2 and 58
.
But 58 is also an even number, so it is divisible by 2. When you do that division, you get
2 and 29 which indicates that 2 * 2 * 29 (which is equivalent to 4 * 29) also multiplies
out to be 116. Therefore, 116 is divisible by 4 and 29.
.
29 is a prime number, so it doesn't factor into any other numbers.
.
In summary, 116 is divisible by the following numbers: 1, 2, 4, 29, 58, and 116.
.
Hope this helps you to understand the problem a little better.
.