Question 1148005
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Let n = the numerator;  then the denominator = (n+2).


The condition says


    n-1 = {{{(1/2)*((n+2)+2)}}}


Multiply both sides by 2 and then simplify


    2n - 2 = ((n+2) + 2

    2n - 2 = n + 4

    2n - n = 4 + 2

     n     = 6


<U>ANSWER</U>.  The numerator is 6;  the denominator is 6+2 = 8.

         The fraction is  {{{6/8}}} = {{{3/4}}}.    <U>ANSWER</U>
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SOLVED.