Question 1147951
{{{log(((x-3)/(5x-7)))=log((1/x))}}}

{{{(x-3)/(5x-7)=1/x}}}

{{{5x-5=x^2-3x}}}

{{{x^2-8x+7=0}}}

{{{(x-7)(x-1)=0}}}


{{{system(x=7,or,cross(x=1))}}}--------









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note:  original equation was {{{log((x-3))-log((5x-7))=log((1/x))}}}.