Question 1147828
z>(x-mean)/sd or 215-202.5 all divided by 8.9
z>12.5/8.9 or >+1.40
probability is 0.0808

for the next part, the numerator is (sample mean-200.70) the denominator is sd/sqrt(n) or 8.9/sqrt(25) or 1.78

z>(200.70-202.5)/1.78
or z>-1.8/1.78 or probability of 0.8438

If the original sample size is normal, the sample may be considered to be normal as well.  Also, there is nothing magic about 30. For normally distributed populations, small samples work.  For skewed, larger ones are needed.
the fraction is now z>12.5/1.78