Question 105605
[1]find the equation of a straight line with slope -1/3 which passes through a point[-2,5] [2]state the gradient and y intercept of these lines [a]3x-4y-12=0 [b]4x+5y=10
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1)point-slope form;
Y-Y1=m(X-X1)
{{{y-5=(-1/3)(x-(-2))}}}
{{{y-5=(-1/3)x-2/3}}}
{{{y=(-1/3)x+13/3}}}
2)a)3x-4y-12=0
Put in slope-intercept form;
-4y=-3x+12
{{{y=(3/4)x-3}}}
slope(gradient)={{{3/4}}}
y-intercept=-3
b)4x+5y=10
5y=-4x+10
{{{y=(-4/5)x+2}}}
{{{gradient = -4/5}}}
y-intercept=2
:)