Question 1147394
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This is  1 - probability that NO ONE af the six cards is a spade.



The probability that the 1-st card in not a spade is  {{{(52-13)/52}}}.

The probability that the 2-nd card in not a spade is  {{{(51-13)/51}}}.

The probability that the 3-rd card in not a spade is  {{{(50-13)/50}}}.

The probability that the 4-th card in not a spade is  {{{(49-13)/49}}}.

The probability that the 5-th card in not a spade is  {{{(48-13)/48}}}.

The probability that the 6-th card in not a spade is  {{{(47-13)/47}}}.


Therefore, the probability under the question is


    P = {{{1 - ((52-13)/52)*((51-13)/51)*((50-13)/50)*((49-13)/49)*((48-13)/48)*((47-13)/47)}}} = 0.8397.    <U>ANSWER</U>
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