Question 105586
{{{y=x^2-5x+3}}}

the axis of symmetry is {{{5/2}}} draw the line perpendicular on {{{x-axis}}} passing thruogh this point


table:

{{{x}}}|{{{y}}}
{{{0}}}|{{{3}}}  _________  if{{{x=0}}} => then{{{y =0^2-5*0+3}}} => {{{y=3}}}
{{{1}}}|{{{-1}}} _________  if{{{x=1}}} => then{{{y =1^2-5*1+3}}} => {{{y=-1}}}

{{{2}}}|{{{-3}}} _________  if{{{x=2}}} => then{{{y =2^2-5*2+3}}} => {{{y=-3}}}

:
:
:and so on



*[invoke solve_quadratic_equation 1, -5, 3]