Question 105585
At time t=0, the bucket is at a height of 64 feet,
{{{h=-16t^2+64}}}
{{{h(0)=-16(0)^2+64}}}
{{{h(0)=64}}}
At what time will the bucket hit the ground, that is, when is the height equal to zero?
{{{h(t)=-16t^2+64=0}}}
{{{-16t^2+64-64=0-64}}}Additive inverse of (64)
{{{-16t^2=-64}}}
{{{-16t^2/(-16)=-64=-16}}}Multiplicative inverse of (-16)
{{{t^2=4}}}
{{{t=2}}}
In takes 2 seconds for the bucket to hit the ground. 
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