Question 1147014
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Jane is 4 years {{{highlight(cross(old))}}} <U>older</U> {{{highlight(cross(then))}}} <U>than</U> Paul. 
The sum of three times janes age and two times Paul’s age is 67. How old are Jane and Paul? 
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Let x be the Jane age;  then the Paul's age is (x-4) years.


From the condition, you have this equation


    3x + 2*(x-4) = 67.


Solve it for x, the Jane's age.


Then evaluate (x-4), the Paul's age.
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