Question 1146989
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Log(12) = log(x) + log(7×x)     (1)


I read 7×x as 7x.  Then  (1) is equivalent to


log(12) = log(x*7x)


log(12) = log(7x^2)


12 = 7x^2


x^2 = {{{12/7}}}


x = {{{sqrt(12/7)}}} = {{{2*sqrt(3/7)}}}.    


<U>ANSWER</U>.   x= {{{2*sqrt(3/7)}}}.
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Solved.



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<U>Be aware</U> :  &nbsp;&nbsp;the "solution" by &nbsp;@josgarithmtic is &nbsp;&nbsp;TOTALLY &nbsp;WRONG &nbsp;(!)


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If you are a novice at this forum, you need to know that @josgarithmetic is a "punishement" of this forum.


    He doesn't know Math;                                                                               (1)

    he can not read the formulation of Math problems correctly;                                         (2)

    he can not solve Math problem correctly and produces every second or third solution incorrectly;    (3)

    he can not explain the solutions in a right way.                                                    (4)


    Every day he tries to prove something to himself and to other tutors, but every time he only proves 
    these statements (1), (2), (3) and (4) again and again.
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