Question 1146903
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<pre>
There are 10 symbols in the word "STATISTICS";


of them,  "S" has multiplicity 3;

          "T" has multiplicity 3;

          "I" has multiplicity 2;

          "A" and "C" have multiplicity 1.


The number of all permutations of 10 items is  10! = 10*9*8*7*6*5*4*3*2*1.


The number of all distinguishable arrangements of letters is  10! / (3! * 3! * 2! * 2!).


The factorials in the denominator serve to account for repeating letters.
</pre>

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See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Arranging-elements-of-sets-containing-undistinguishable-elements.lesson>Arranging elements of sets containing indistinguishable elements</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Combinatorics: Combinations and permutations</U>". 



Save the link to this textbook together with its description


Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson


into your archive and use when it is needed.