Question 105574
Given:
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{{{8(1+1/2)^2 +22(1+1/t)+15=0}}}
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Inside the first set of parentheses, add the {{{1 + 1/2}}} which is the same as {{{1 + .5}}}
to get {{{1.5}}}. Then square that quantity to get {{{1.5^2 = 2.25}}}. This reduces the
problem to:
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{{{8*2.25 + 22(1+ 1/t) + 15 = 0}}}
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Multiplying the 8 times 2.25 results in 18 and the problem then is simplified to:
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{{{18 + 22(1 + 1/t) + 15 = 0}}}
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Next, multiply the 22 times each of the terms in the remaining set of parentheses. The
22 times the 1 is 22 and the 22 times the {{{1/t}}} is {{{22/t}}}. This makes the equation
become:
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{{{18 + 22 + 22/t + 15 = 0}}}
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Then combine the 18 with the +22 and the +15 to get the sum 55. The equation is then:
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{{{55 + 22/t = 0}}}
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By subtracting 55 from both sides you separate the two terms and make the equation:
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{{{22/t = -55}}}
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Multiply both sides of this equation by t to eliminate the denominator and make the equation:
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{{{22 = -55t}}}
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Solve for t by dividing both sides by -55 and you have:
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{{{t = 22/(-55)}}}
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Notice that both the numerator and the denominator have a common factor of 11. So you can
simplify the answer by dividing both by 11 to get:
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{{{t = 2/(-5) = -2/5}}}
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Hope this helps you to understand the problem.