Question 1146838
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<pre>
This is a binomial distribution type problem where the probability under the question is the sum


     P = {{{sum (C(10,k)*p^k*q^(10-k),k=6,10)}}}      (1)


The number of trials is              10;
The indexes of success trials        k = 6,7,8,9,10
The probability of success trial     p = 0.6;
                                     q = 1 - p
C(n,k) = n! / (k! * (n-k)!)          are binomial coefficients.


The sum  (1)  is equal to  1 - {{{sum(C(10,k)*p^k*q^(10-k),k=0,5)}}}.     (2)



Instead of calculating every term of (2) manually and then summing them up, you may use Excel function 

BINOM.DIST(5, 10, 0.6, TRUE)  to calculate the value


    {{{sum(C(10,k)*p^k*q^(10-k),k=0,5)}}} = 0.366897.    


Therefore, the value of  (2)  is equal to  1 - 0.366897 = 0.633103 (approximately).    <U>ANSWER</U>
</pre>

On Excel function BINOM.DIST, see its description everywhere, for example


https://support.office.com/en-us/article/binom-dist-function-c5ae37b6-f39c-4be2-94c2-509a1480770c