Question 1146804
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Clearly he can only have either 1 quarter or none.<br>
(1) If he has a quarter, that is 25 of the 40 cents; 15 cents remain.  He can have either 1 dime or no dimes; nickels will make up the rest.<br>
2 solutions with 1 quarter.<br>
(2) If he has no quarters, then the number of dimes he can have is any number from 0 to 4; again nickels will make up the rest.<br>
5 solutions with no quarters.<br>
Total number of combinations: 2+5 = 7<br>