Question 104111
Before we proceed, read my lesson,"An overview to the laws of logarithms" first then, go back to this page.



Using the logarithm,

{{{5^2x+1 = 125^x}}}
{{{log(5^2x+1) = log(125^x)}}}
{{{2x+1(log (5))=x log (125)}}}
{{{2x+1(log (5))=x log (5^3)}}}
{{{2x+1(log (5))=x (3 log(5))}}}
{{{(2x+1(log (5)))/log(5)=(x (3 log (5)))/log(5)}}}
{{{2x+1=3x}}}
{{{2x-2x+1=3x-2x}}}
{{{x=1}}}


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HyperBrain!