Question 105538

{{{b/2+(b-1)/3=(b-2)/4}}}
If you multiply both sides by 12,
{{{12(b/2+(b-1)/3)=12((b-2)/4)}}}
{{{6b+4(b-1)=3(b-2)}}}
{{{6b+(4b-4)=3b-6}}}
{{{(6b+4b)-4=3b-6}}}
{{{10b-4=3b-6}}}
{{{10b-4+4=3b-6+4}}}
{{{10b=3b-2}}}
{{{10b-3b=3b-3b-2}}}
{{{7b=-2}}}
{{{b=-2/7}}}

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