Question 105511
{{{ f(x)= (2x^2)/(x+2) }}}
Assymptotes:
..vertical: x, when denominator is zero. x=-2
..horizontal: there is none because the degree of the numerator is greater than the degree of the denominator.
..y intercept occurs when x=0 f(x)=y=0
..x intercept occurs when y=0 x=0
.
{{{ f(x)= (-4)/(x^2+1) }}}
..Horizontal assymptote: Since the degree of the denominator is greater than the numerator the assymptote is the line y=0 
..Vertical assymptote: there is none because the denominator never can become negative.
I'll let you calculate the x and y intercepts from what I told you above.
Ed
{{{graph(500,500,-10,10,-25,10,(2x^2)/(x+2))}}}
.
{{{graph(500,500,-10,10,-10,10,-4/(x^2+1))}}}