Question 1146702
<br>
{{{R(x) =  (300-15x)(5+0.50x) = -7.5x^2+75x+1500}}}<br>
The maximum value of the quadratic function y = ax^2+bx+c is when {{{x = -b/(2a)}}}.  Use that to find the desired value of x.<br>
Then remember that "x" is not the answer to the question; the answers to the two questions are
(1) the maximum revenue, {{{(300-15x)(5+0.50x)}}}, and
(2) the admission price that will yield that maximum revenue, {{{5+0.5x}}}<br>