<PRE><B>Question 1146565</B>
Maximum revenue maximizes -0.2x^2+71x, where a=-0.2 and b=71
the x-value for this quadratic&#39;s maximum if -b/2a=-71/-0.4 or 177.5 watches
177 revenue is 
$18832.80
178 revenue is $6301.20
177 revenue is $6301.20
either of those maximizes revenue
profit function is their difference or -0.2x^2+45x-1600=P(x)


{{{graph(300,300,-100,200,-1000,7000,-.2x^2+71x,26x+1600,-0.2x^2+45x-1600)}}}
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