Question 1146387
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For the sum of two different positive integers to be 30, the largest possible value for the smaller of the two is 14.<br>
So the worst case is to draw all the numbers from 15 to 100 before drawing any number less than 15.<br>
That's 86 numbers, from 15 to 100 inclusive, without having a sum of 30 with two of them.<br>
Then the 87th number will be less than 15; it will match up with a number already drawn to make a sum of 30.<br>
ANSWER: 87 numbers need to be drawn to assure that two of them have a sum of 30.