Question 1146276

How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)
<pre>Equation of a parabola in vertex-form : {{{matrix(1,3, y, "=", a(x - h)^2 + k)}}}, with:
                                        (h, k) being the coordinates of the vertex of the parabola
                                        (x, y) being a point on the parabola
                                        "a" being the width and location of the parabola
{{{matrix(1,3, 6, "=", a(0 - - 3)^2 - 3)}}} ------ Substituting (- 3, - 3) for (h, k) and (0, 6) for (x, y) in order to determine the value of "a." 
6 = 9a - 3
6 + 3 = 9a
9 = 9a
{{{matrix(1,5, 9/9, "or", 1, "=", a)}}}
Equation of parabola in vertex-form: {{{highlight_green(matrix(1,3, y, "=", (x + 3)^2 - 3))}}}