Question 1146276
How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)
:
Using this form, ax^2 + bx + c = y
x=-3, c=6, y=-3, Assume a=1
9(1) - 3b + 6 = -3
find b
-3b + 15 = -3
=3b = -3 -15
-3b = -18
b = -18/-3
b = 6
The equation: y = x^2 + 6x + 6
Graphically
{{{ graph( 300, 200, -6, 5, -5, 7, x^2+6x+6) }}}