Question 1146267
normal approximation may be used
mean is np=0.6*800=480
variance is np(1-p)=400*.4=160
sd is sqrt (160)=12.65
z=(x-mean)/sd
=(517.5-480)/12.65
=37.5/12.65
=2.90
probability of z>2.90 is 0.002
It would be unusual.