Question 1146128
One (the first) number is five less than a second number. Three times the first is 12 more than 6 times the second. Find the numbers.
<pre>
Second number = N
First number = five less than the second number = N-5 (take 5 away)
Three times the first = 3(N-5)
6 times the second = 6N
12 more than 6 times the second = 6N+12 (add 12)

{{{matrix(9,3,
(matrix(4,1,Three,times,the,first)), is,
(matrix(7,1,12,more,than,6,times,the, second)),
"","","",
3(N-5),""="",6N+12,
3N-15,""="",6N+12,
-3N,""="",27,
N,""="",-9,
(matrix(2,1,second,number)),""="",-9,
(matrix(2,1,first,number)),""="",-9-5,
(matrix(2,1,first,number)),""="",-14


)}}}

Edwin</pre>