<PRE><B>Question 1146085</B>
&lt;br&gt;
Solve the linear equation for one of the variables.&lt;br&gt;
{{{4x+2y = 24}}}
{{{2x+y = 12}}}
{{{y = 12-2x}}}&lt;br&gt;
Substitute&lt;br&gt;
{{{x^2+y^2 = x^2+(12-2x)^2 = 5x^2-48x+144}}}&lt;br&gt;
The minimum value of a quadratic function is when x = -b/2a = 48/10 = 24/5.&lt;br&gt;
{{{y = 12-2x = 12-48/5 = 12/5}}}&lt;br&gt;
ANSWERS: x = 24/5; y = 12/5</PRE>