Question 1145938
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            The solution by tutor @rothauserc is not precisely correct, therefore I came to bring corrected solution.



<pre>
Since the height of the building is given in feet, we will use 32 feet per second squared as the acceleration of gravity

distance(s) = 0.5 * at^2, where a is acceleration of gravity and t is the time it takes for the hammer to hit the ground

0.5 * 32 * t^2 = 300

t^2 = 300/16 = 18.75

t = 4.33 seconds

(a) average velocity(v) = {{{(a*t)/2}}} = {{{(32*4.33)/2}}} =  69.28 feet/sec  <<<---===  <U>my correction is in this line</U>

(b) instantaneous velocity = at = 32 * 4.33 = 138.56 feet/sec
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