Question 105200
{{{((b-2) /(b^2-4))/((b^2+b)/(b+1))}}}
Let's begin by separating and simplifying the numerator and the denominator;
{{{(b-2)/(b^2-4)}}}
{{{(b-2)/(b-2)(b+2)}}}
{{{cross(b-2)/cross(b-2)(b+2)=1/(b+2)}}}
Now the denominator;
{{{(b^2+b)/(b+1)}}}
{{{(b(b+1))/(b+1)}}}
{{{(b)cross(b+1)/cross(b+1)=b/1}}}
Now lets divide the two'
{{{(1/(b+2))/(b/1)}}}
When you divide fractions, you multiply the numerator by the reciprocal of the denominator;
{{{(1/(b+2))*(1/b)=(1)/(b^2+2b)}}}
:)