Question 1145868
.


This problem is on Binomial distribution.


<pre>
Use the Binomial Probability formula


    Probability (P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)


For this problem, n = 4, k = 2, p = 45% = 0.45.


Therefore,


    P = 4C2 * (0.45)^2 * (1-0.45)^(4-2) = {{{((4*3)/(1*2))*0.45^2*0.55^2}}} = 0.3675 = 36.75%
</pre>

Solved.