Question 1145710
A) Because np, and  n(1-p) _are both__greater than or equal to__ ____ ​10, the sample size is __less than__ ​5% of the population​ size, and the sample ____________can be reasonably assumed to be random_________,the requirements for testing the hypothesis ___are___ satisfied.



np, n(1-p) > = 10 

np = 885*0.0215 

     = 19.0275



 n(1-p) = 885*(1 - 0.0215)

            = 865.9725



Hypotheses: 

B) What are the null and alternative​ hypotheses?

H0​: P = 0.018  versus   H1​: P > 0.018



C) Find the test​ statistic, z

n = 885

p-hat = 19/885

         = 0.0215



P = 0.018

q = 1 - p

   = 1 - 0.018

q  = 0.982



Z = ( ( p-hat) - p )/√(p*q/n)

Z = ( 0.0215  - 0.018)/√( (0.018*0.982)/ 885 )

Z = 0.78





D) Find the​ P-value.

​The area under the curve for z = 0.78 is 0.7823, Subtract the area from 1 to obtain the p-value,

p- value  = 1 - 0.7823

p - value  = 0.218



Since ​P-value>α​, do not reject the null hypothesis and conclude that there is not sufficient evidence that more than1.8​% of the users experience flulike symptoms.

Since P- value (0.218 ) > 0.01, we fail to reject the null hypothesis .