Question 1145650
Find the shortest distance from the origin to the graph of the circle with equation given below.


x^2−12x+y^2−12y+36=0
-----------
Find the center of the circle and its radius.
x^2−12x+y^2−12y+36=0
x^2−12x+y^2−12y = -36
(x-6)^2 + (y-6)^2 = -36 + 36 + 36 = 36
The center is (6,6) and the radius is 6.
------
Find the distance d to the center.
{{{d = sqrt(6^2 + 6^2) = 6sqrt(2)}}}
----------
Subtract the radius if d is > radius.
Distance = {{{6sqrt(2) - 6}}}