Question 1145599
{{{drawing(14000/57,400,-.5,3,-.5,5.2,
red(arc(0,4.87,2,-2,298,360)), locate(-.2,5,P),
red(arc(2.568,0,2,-2,117.8,180)),
locate(-.5,2.4,4870),locate(0.3,4.8,62.2^o),
locate(.8,0,TRAIN),locate(1,.3,x), locate(1.7,.5,62.2^o),
line(0,0,2.568),line(0,0,0,4.870), line(2.568,0,0,4.87),
green(line(0,4.870,1.37,4.870)) )}}}
<pre>

The plane is at point P.  The train is at the bottom of the
triangle. The angle of elevation from the plane down to the
end of the train is the same as the angle of elevation from 
the end of the train up to the plane. The train has length
x meters.
 
Now, with the above drawing, Tatiana's solution makes 
some sense:

{{{tan(62.2)=4870/x}}}
{{{x=4870/tan(62.2)}}}
{{{x=2567.66}}}m 

Edwin</pre>