Question 1145566
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Y=-(x+1)^2+3

a)	Find the X- and Y- intercepts (2 points) 
b)	Find the maximum or minimum values (2 points)
c)	Sketch the function.
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(a)
Let x be 0 and solve for y.
Let y be 0 and solve for x.


(b)
Read from the equation in the form you are given.
Maximum point is  (-1, 3).
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(?)----Look at the form of the equation!  Certain values in their places tell you the coordinates for the vertex, and that it is a maximum point.
Starting with y=x^2, if change to y=-x^2, this reflects through the x axis at the vertex.   Change to y=-(x-h)^2, will move entire graph h units to the right if h is positive.  Change to y=-(x-h)^2+k, will move entire graph up by k units if k is positive.


(c)
{{{graph(400,400,-4,4,-4,4,-(x+1)^2+3)}}}