Question 1145450
The perimeter of a rectangular dining room is 18 meters. The area is 18 square meters. What are the dimensions of the dining room?
<pre>Let length and width be L and W, respectively
Then we get: 2(L + W) = 18_______2(L + W) = 2(9)______L + W = 9______L = 9 - W ---- eq (i)
Also, LW = 18 ------ eq (ii)
W(9 - W) = 18 ------ Substituting 9 - W for L
{{{matrix(1,3, 9W - W^2, "=", 18)}}}
{{{matrix(1,3, 0, "=", W^2 - 9W + 18)}}}
0 = (W - 6)(W - 3)
W - 6 = 0             OR                 W - 3 = 0
W, or width = 6       OR                 W = 3
If width = 6, then length = 3(9 - 6), and VICE-VERSA.
{{{highlight_green(matrix(1,6, "Dimensions:", 6, m, by, 3, m))}}}