Question 1145387
Hi
First draw a right angled triangle ABC
Angle ABC = 90 degrees
Angle ACB = 66 degrees (given)
Extend BC out a distance to D. CD = 300 ft.
Draw a line from point D to point A
Angle ADC = 54 degrees.
If angle ACB = 66 deg. then angle ACD = 114 deg
This allows you to find angle DAC = 12 deg.
Using sine rule: a/sin A = d/sin D
300/sin (12) = x/ sin (54)
x = (300 * sin (54))/ sin (12)
x = 1167.35 ft
AC = 1167.35
Triangle ABC
AC = 1167.35
Angle c = 66 deg.
Using Sin = Oppos/Hyp : Sin (66) = Oppos/1167.35
Therefore Opposite (AB) = sin (66) * 1167.35 = 1066.43 feet (the height of the building.)
Hope this helps :-)