Question 1145326
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This is a straightforward application of binomial probability.  The probability that a particular camera is faulty is 0.075, so the probability that it is not defective is 0.925.<br>
You won't learn anything by having us do the calculations for you, so I leave that to you.  Here is what you need<br>
{{{P(x=0) = (4C0)*(0.075)^0*(0.925)^4}}}<br>
{{{P(x=1) = (4C1)*(0.075)^1*(0.925)^3}}}<br>
{{{P(x=2) = (4C2)*(0.075)^2*(0.925)^2}}}<br>
{{{P(x=3) = (4C3)*(0.075)^3*(0.925)^1}}}<br>
{{{P(x=4) = (4C4)*(0.075)^4*(0.925)^0}}}<br>
To check your calculations you can verify that the sum of those probabilities is equal to 1.