Question 1145227
{{{A=A[o]e^(kt)}}}


If t=0 were 8 years ago, and t=8 were today, then 
{{{840=1470*e^(8k)}}}
{{{840/1470=e^(8k)}}}
{{{0.57142857142=e^(8k)}}}
{{{ln(0.57142857142)=8k}}}
{{{k=-0.069952}}}
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Model Equation,  {{{highlight_green(A=840*e^(-.069952t))}}}
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