Question 1145242
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There is nothing wrong with the solution shown by tutor @josgarithmetic.  However, they made the problem much more work than necessary!<br>
The obvious two equations from the given information are<br>
{{{j = w+5}}}
{{{2(j+2) = 4(w-1)}}}<br>
Given two equations in that form, the easiest solution method is substitution.<br>
But the other tutor went to the trouble of solving the second equation for j and substituting in the first equation, leading to a lot of calculations involving fractions.<br>
It is rather silly to do that, when the first equation already gives you one variable in terms of the other!<br>
So substitute what's given in the first equation into the second:<br>
{{{2((w+5)+2) = 4(w-1)}}}
{{{2w+14 = 4w-4}}}
{{{18 = 2w}}}
{{{w = 9}}}<br>
So Will is 9; that makes John 9+5 = 14.