Question 1145168
x-10/6 >= x-5/9 + 7/18
<pre>
You didn't put in any parentheses so there is no way for us to tell what's
in the numerators.  The way you have it means

{{{x-10/6 >= x-5/9 + 7/18}}}

and if we subtract x from both sides, there are no variables.

{{{-10/6 >= -5/9 + 7/18}}}

which becomes

{{{-5/3 >= -1/6}}}

But that's false, so I know you didn't mean what you wrote.

Did you mean parentheses around x-10 and x-5, like this?

(x-10)/6 >= (x-5)/9 + 7/18

If so that would mean this:

{{{(x-10)/6 >= (x-5)/9 + 7/18}}}

Multiply through by the LCD of 18

{{{18*((x-10)/6) >= 18*((x-5)/9) + 18*(7/18)}}}

{{{3(x-10) >=2(x-5)+7}}}

Solve that just like an equation.

Edwin</pre>